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Implement matchregexp() using fnmatch()

This commit is contained in:
Kim Woelders 2021-11-13 08:07:10 +01:00
parent 2db8cc269f
commit d045a86c5c
1 changed files with 4 additions and 87 deletions
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91
src/regex.c
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@ -1,5 +1,6 @@
/*
* Copyright (C) 2000-2007 Carsten Haitzler, Geoff Harrison and various contributors
* Copyright (C) 2021 Kim Woelders
*
* Permission is hereby granted, free of charge, to any person obtaining a copy
* of this software and associated documentation files (the "Software"), to
@ -22,97 +23,13 @@
*/
#include "E.h"
static int
isafter(int p, const char *s1, const char *s2)
{
int i, j;
int len, len2;
int match;
len = strlen(s1);
len2 = strlen(s2);
match = 0;
for (i = p; i < len; i++)
{
if (s1[i] == s2[0])
{
match = 1;
for (j = 0; j < len2; j++)
{
if ((i + j) >= len)
return -1;
if (s1[i + j] != s2[j])
match = 0;
}
}
if (match)
return i + len2;
}
return -1;
}
#include <fnmatch.h>
int
matchregexp(const char *rx, const char *s)
{
int i, l, m;
int len, lenr;
int match;
char rx2[1024];
if (!s)
return 0;
if (!rx)
if (!rx || !s)
return 0;
len = strlen(s);
l = 0;
lenr = 0;
match = 1;
if ((strcmp(rx, "*") || rx[0] == 0) && s[0] == 0)
return 0;
if (rx[0] != '*')
{
m = 0;
while ((rx[l] != '*') && (rx[l]) && (m < 1023))
rx2[m++] = rx[l++];
rx2[m] = 0;
lenr = strlen(rx2);
if (lenr > len)
return 0;
for (i = 0; i < lenr; i++)
{
if (s[i] != rx[i])
return 0;
}
}
if ((!rx[l]) && (s[lenr]))
return 0;
for (i = lenr; i < len;)
{
if (rx[l])
l++;
if (rx[l])
{
m = 0;
while ((rx[l] != '*') && (rx[l]) && (m < 1023))
rx2[m++] = rx[l++];
rx2[m] = 0;
i = isafter(i, s, rx2);
if (i < 0)
return 0;
}
else
{
// We arrived at the end of the regex BUT if it doesn't
// end with the wildcard * and there are more chars
// in s remaining to be matched, we should return 0
if ((i < len) && (rx[l - 1] != '*'))
return 0;
else
return match;
}
}
return match;
return !fnmatch(rx, s, 0);
}